Leibnitz's Theorem

Leibniz's theorem states the time derivative of the integral of \( F(x,t) \) between \( x = a(t) \) and \( x = b(t) \) is \[ \frac{d}{dt} \int_{x = a(t)}^{x = b(t)} F(x,t)\, dx = \int_{a}^{b} \frac{\partial F}{\partial t} \, dx + \frac{db}{dt} F(b,t) - \frac{da}{dt} F(a,t) \]

Example: Find \( \frac{d}{dt} \int_{x=0}^{x=ct} e^{-x^2} \, dx \) This integral cannot be solved in closed form and then differentiated. However, with Leibniz’s rule, the solution is easily found

\( \because a(t) = 0 , b(t) = ct, F(x,t) = e^{-x^2} \therefore \frac{da}{dt} = 0 , \frac{db}{dt} = c, \frac{\partial F}{\partial t} = 0 \) \( \therefore \frac{d}{dt} \int_0^{ct} e^{-x^2} \, dx = 0 + c \cdot e^{-b^2} - 0 = \boxed{c e^{-c^2 t^2}} \)

The one-dimensional Leibniz theorem can be extended to three dimensions (volume and area integrals) as follows \[ \frac{d}{dt} \int_{V(t)} F(\vec{x}, t) dV = \int_{V(t)} \frac{\partial F(\vec{x}, t)}{\partial t} dV + \oint_{A(t)} F(\vec{x}, t) \vec{u}_A \cdot d\vec{A} \]

\[ \underbrace{\frac{d}{dt} \int_{V(t)} F(\vec{x}, t) \, dV}_{\text{Total rate of change of } F} = \underbrace{\int_{V(t)} \frac{\partial F(\vec{x}, t)}{\partial t} \, dV}_{\text{Rate of change of } F \text{ due to unsteadiness of } F \text{ itself}} + \underbrace{\oint_{A(t)} F(\vec{x}, t) \vec{u}_A \cdot d\vec{A}}_{\text{Rate of change of } F \text{ due to movement of the volume's boundary}} \]

1John M. Cimbala. ME 320 Fluid Flow.